Mechanical Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 5 (Q.No. 45)
45.
When the shear force diagram between any two points is an inclined straight line, it indicates that there is a uniformly varying load between the two points.
Yes
No
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
15 comments Page 1 of 2.

Sohel said:   8 years ago
SF Diagram :: Point Load - Straight Line
UDL - Inclined Line
UVL - Parabolic Line

BM Diagram :: Point Load - Inclined Line
UDL - Parabolic Line
UVL - Hyperbolic/Cubic Line
(3)

Biswamitra nag said:   9 years ago
At a point in a strained bodu there are stresses 700 N/mm2 compressive & 50 N/mm2 tensile acting on two mutually perpendicular planes together with the shear stress of 30 N/mm2. Locate the principle planes & find the values of principle stresses.

Harshdeepsinh said:   6 years ago
SFD is given as an inclined straight line that doesn't mean it's a UVL. If load distribution is given as an inclined straight line then we can say that it's UVL.

Sridhar said:   6 years ago
Simply supported and cantilever beam the uniformly varying load for shear force diagram is parabolic curve only so the answer is a parabolic curve.

Vijay said:   9 years ago
It's is parabolic not an inclined line. For Variable distribution loads Share force diagram is parabolic and Bending moment diagram is cubic.

Arun said:   4 years ago
NO. If its inclined straight line, then the load is Uniformly distrubuted load and if its parabolic, then the load is Uniformly varying load.
(3)

Gaurav said:   1 decade ago
Correct answer is B.

SFD for UDL- Inclined straight.

SFD for VDL- Parabolic.

Jhh said:   1 decade ago
This is wrong answer the answer will be no because sfd for vds is parabolic.

Joyi said:   8 years ago
sfd for the udl-inclined straight line.
sfd for uvl-parabolic.

Dilip Reddy said:   8 years ago
It's a wrong answer, for VDL the SFD will be parabolic.


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