Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 5 (Q.No. 45)
45.
When the shear force diagram between any two points is an inclined straight line, it indicates that there is a uniformly varying load between the two points.
Discussion:
15 comments Page 1 of 2.
Sohel said:
8 years ago
SF Diagram :: Point Load - Straight Line
UDL - Inclined Line
UVL - Parabolic Line
BM Diagram :: Point Load - Inclined Line
UDL - Parabolic Line
UVL - Hyperbolic/Cubic Line
UDL - Inclined Line
UVL - Parabolic Line
BM Diagram :: Point Load - Inclined Line
UDL - Parabolic Line
UVL - Hyperbolic/Cubic Line
(3)
Arun said:
4 years ago
NO. If its inclined straight line, then the load is Uniformly distrubuted load and if its parabolic, then the load is Uniformly varying load.
(3)
Tarik said:
5 years ago
Answer should be No.
(1)
Vikash said:
5 years ago
Udl will be the right answer.
(1)
Jhh said:
1 decade ago
This is wrong answer the answer will be no because sfd for vds is parabolic.
Gaurav said:
1 decade ago
Correct answer is B.
SFD for UDL- Inclined straight.
SFD for VDL- Parabolic.
SFD for UDL- Inclined straight.
SFD for VDL- Parabolic.
Biswamitra nag said:
9 years ago
At a point in a strained bodu there are stresses 700 N/mm2 compressive & 50 N/mm2 tensile acting on two mutually perpendicular planes together with the shear stress of 30 N/mm2. Locate the principle planes & find the values of principle stresses.
Vijay said:
9 years ago
It's is parabolic not an inclined line. For Variable distribution loads Share force diagram is parabolic and Bending moment diagram is cubic.
Dilip Reddy said:
8 years ago
It's a wrong answer, for VDL the SFD will be parabolic.
Sandas said:
8 years ago
It's parabolic.
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