Mechanical Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 4 (Q.No. 12)
12.
The radius of the Mohr 's circle in the given figure is equal to
sum of two principal stresses
difference of two principal stresses
half the sum of two principal stresses
half the difference of two principal stresses
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
3 comments Page 1 of 1.

Amit said:   4 years ago
You are correct, Thanks @Sandip.

Sandip Karmakar said:   8 years ago
It is maximum shear stress(f1-f2)/2.

Anurup said:   8 years ago
Here, it is f1 - f2/2.

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