Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 2 (Q.No. 39)
39.
A body is subjected to two normal stresses 20 kN/m2 (tensile) and 10 kN/m2 (compressive) acting perpendicular to each other. The maximum shear stress is
Discussion:
26 comments Page 1 of 3.
Prateek kumar said:
7 years ago
The maximum shear stress is the radius of Mohr's circle.
ie, √(σx- σy/2)^2 + τxy^2.
Thus σy is compressive so negative.
σx-(- σy)/2 root and square get cancelled.
So, (20+10)/2 = 15 KN/m^2 ans.
ie, √(σx- σy/2)^2 + τxy^2.
Thus σy is compressive so negative.
σx-(- σy)/2 root and square get cancelled.
So, (20+10)/2 = 15 KN/m^2 ans.
Abhishek Aryan said:
8 years ago
@Hardik.
IN THIS CASE, sigma(max) is 20 and sigma(min) is -10, and the formula to get max shear stress is [sigma(max)- sigma(min)]/2 so it would give us 15 or [20-(-10)]/2 = 15.
IN THIS CASE, sigma(max) is 20 and sigma(min) is -10, and the formula to get max shear stress is [sigma(max)- sigma(min)]/2 so it would give us 15 or [20-(-10)]/2 = 15.
Hardik said:
8 years ago
Is that necessary to keep the numbers in a single equation? Couldn't it be possible that its like (20-10)-2, and if it's wrong what the reason behind this. Is there any formula?
Suresh said:
7 years ago
Max shear stress = √((sigma max +sigma min)/2)^2 + (shear stress)^2.
Here, σ max 20 and σ min -10(compressive). Shear stress is zero (if not given).
Here, σ max 20 and σ min -10(compressive). Shear stress is zero (if not given).
Tapas said:
5 years ago
Since the tensile and compressive stresses are in opposite direction, therefore the sign convention of these stresses should also be in opposite direction.
Jyoshna said:
8 years ago
Tensile(+) ; comp(-ve) formula max shear stress is (sigma1 - sigma2)÷2.
Sigma1=20, sigma2=10.
Now substitute [+20 -(-10)]÷22 =15.
Sigma1=20, sigma2=10.
Now substitute [+20 -(-10)]÷22 =15.
D rahul said:
9 years ago
@Sandeep
The correct method for max. shear stress is (max. principal stress - min. principal stress)/2.
i.e answer must be 5.
The correct method for max. shear stress is (max. principal stress - min. principal stress)/2.
i.e answer must be 5.
Sagar m said:
1 decade ago
Answer is right. Because,
Compressive stress value will be taken as negative. So,
20-(-10)/2 = (20+10)/2=15KN/m2.
Compressive stress value will be taken as negative. So,
20-(-10)/2 = (20+10)/2=15KN/m2.
Sandeep m said:
1 decade ago
Max. Shear stress = Tensile stress - Compressive stress\2.
Compressive stress taken as negative.
Answer is 15.
Compressive stress taken as negative.
Answer is 15.
Bijo rajan said:
7 years ago
Actually maximum means to add them, and the compression is in a negative sign it gets reduced and becomes minus.
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