Mechanical Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 2 (Q.No. 39)
39.
A body is subjected to two normal stresses 20 kN/m2 (tensile) and 10 kN/m2 (compressive) acting perpendicular to each other. The maximum shear stress is
5 kN/m2
10 kN/m2
15 kN/m2
20 kN/m2
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
26 comments Page 3 of 3.

Ch v gopinath said:   8 years ago
[20-(-10)]/2.

The y-axis is compressive.

Akshay tc said:   8 years ago
5 or 15?

Please explain the answer.

Sumit said:   7 years ago
Here, it comes (20+10/2).

Adhikary saroj said:   9 years ago
Answer is c. I agree.

Mdsufiyan said:   8 years ago
How to calculate it?

Krishna said:   1 decade ago
How to calculate?


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