Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 17)
17.
The maximum diameter of the hole that can be punched from a plate of maximum shear stress 1/4th of its maximum crushing stress of punch, is equal to (where t = Thickness of the plate)
Discussion:
65 comments Page 3 of 7.
Ajitesh said:
9 years ago
σs = (1/4)σc.
F/(Φ d.t) = F/((Φ/4).d^2.t).
d = t.
F/(Φ d.t) = F/((Φ/4).d^2.t).
d = t.
NITESH BORKAR said:
9 years ago
The equation will be:
(Pi/4 * d^2) * Crushing strength,
= Pi * d * t * Shear strength (or crushing strength * 2).
Which comes out to be t only.
(Pi/4 * d^2) * Crushing strength,
= Pi * d * t * Shear strength (or crushing strength * 2).
Which comes out to be t only.
Deepak said:
9 years ago
S.S = ( 1/4) * C.S.
F/Pi dt = (1/4) * (4F/pi * d^2).
Thus, d = t.
F/Pi dt = (1/4) * (4F/pi * d^2).
Thus, d = t.
Indrajeet said:
9 years ago
Option A is the correct answer.
Crushing stress = 4 * Load(P)/φ * D * D.
Shear stress = Load(P)/φ * D * t.
Since Crushing stress = 4 * Shear stress.
After resolve, We get, D = t.
So option A is right.
Crushing stress = 4 * Load(P)/φ * D * D.
Shear stress = Load(P)/φ * D * t.
Since Crushing stress = 4 * Shear stress.
After resolve, We get, D = t.
So option A is right.
Sridevi said:
9 years ago
Yes, agree that d = t.
Koribilli hemanth said:
9 years ago
Answer was wrong.
The right answer is T = D.
Shear force = pi * D * T * shear stress.
Crushing force = (pi/4) * D^2 * crushing stress.
The condition is that "crushing stress = 4 * shear stress " at equilibrium condition " shear force = crushing force"
pi * D * T * shear stress = (pi/4) * D^2 * crushing stress.
By canceling the terms finally we will get D = T.
The right answer is T = D.
Shear force = pi * D * T * shear stress.
Crushing force = (pi/4) * D^2 * crushing stress.
The condition is that "crushing stress = 4 * shear stress " at equilibrium condition " shear force = crushing force"
pi * D * T * shear stress = (pi/4) * D^2 * crushing stress.
By canceling the terms finally we will get D = T.
Ananth said:
9 years ago
Shear stress = Load(P)/φ * D * t.
φ * D * t = ?
(area= L*T or (φ * D2)/4).
φ * D * t = ?
(area= L*T or (φ * D2)/4).
Rabin said:
9 years ago
The question has asked the maximum diameter that can be punched. I think the smallest diameter should be equal to t. But again, I don't know how. Please explain in most basic tone.
Himanshu said:
9 years ago
d = t is the answer.
Saumya singh said:
9 years ago
d = t is the answer.
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