Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 17)
17.
The maximum diameter of the hole that can be punched from a plate of maximum shear stress 1/4th of its maximum crushing stress of punch, is equal to (where t = Thickness of the plate)
Discussion:
65 comments Page 1 of 7.
Sharan said:
1 decade ago
Shear stress = force/area.
Area = length*thickness.
So, 1/4 shear stress = l*t.
Stress = 4*t*l.
Area = length*thickness.
So, 1/4 shear stress = l*t.
Stress = 4*t*l.
Jammy khan said:
1 decade ago
Shear stress = F/A.
F = 1/4, A = L*thickness.
Put the value in given equation,
Shear stress = (4/1)*(L*thickness).
F = 1/4, A = L*thickness.
Put the value in given equation,
Shear stress = (4/1)*(L*thickness).
Rajesh said:
1 decade ago
Max.shear stress of plate = 1/4 of max crushing stress.
And plate thickness = t.
We know, shear stress = L*t and crushing stress = d*L.
Therefore,L*t = 1/4 of max. crushing stress.
or, 4*t*L = crushing stress=d*L.
or, 4t = dia of hole.
And plate thickness = t.
We know, shear stress = L*t and crushing stress = d*L.
Therefore,L*t = 1/4 of max. crushing stress.
or, 4*t*L = crushing stress=d*L.
or, 4t = dia of hole.
Akshay said:
1 decade ago
How is shear stress equal to l*t?
Kuruu said:
1 decade ago
@Akshay I want to explain you about the question.
Actually @Rajesh had done exactly no need again just check once if at all u didnt get that will see.
Actually @Rajesh had done exactly no need again just check once if at all u didnt get that will see.
Satya said:
1 decade ago
Shear stress = Pi/4*d2*load.
Crushing stress = load*d*t.
Given that s.s = 1/4*c.s.
Solving this we get d = t/pi.
Crushing stress = load*d*t.
Given that s.s = 1/4*c.s.
Solving this we get d = t/pi.
UPPU HARISH said:
1 decade ago
I couldn't understand this.
If we take a punch punching a hole in a plate then,
Shear stress = P/pi*D*t.
Crushing stress = 4*P/pi*D*D.
When these two are equated with the relation given then we get d=t.
Please tell me where I am wrong?
If we take a punch punching a hole in a plate then,
Shear stress = P/pi*D*t.
Crushing stress = 4*P/pi*D*D.
When these two are equated with the relation given then we get d=t.
Please tell me where I am wrong?
Srikanth said:
1 decade ago
How could it be @Rajesh there is nothing explained in your answer. Can you please explain it briefly?
Biswajit Roy said:
1 decade ago
Shear stress*Pi*dt = Crushing stress*Pi*d^2/4.
d = t.
If wrong why?
d = t.
If wrong why?
Shalabh Suradhaniwar said:
1 decade ago
@Uppu Harish perfect answer & absolute correct explanation.
d=t, shall be the correct answer.
Crystal clear depiction of force & area in shear & crush.
d=t, shall be the correct answer.
Crystal clear depiction of force & area in shear & crush.
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