Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 17)
17.
The maximum diameter of the hole that can be punched from a plate of maximum shear stress 1/4th of its maximum crushing stress of punch, is equal to (where t = Thickness of the plate)
Discussion:
65 comments Page 2 of 7.
Adarsh said:
1 decade ago
min d = [4t(max ss of plate)/max crushing stress of punch].
MANPREET SINGH said:
1 decade ago
Shear stress = Crushing stress in rivet joint.
Rajeeev said:
10 years ago
D = T should be correct answer.
Shiyas said:
10 years ago
Answer is A.
(pi*(D^2) /4)*Crushing stress = pi*D*t*(Crushing stress/4).
===> D=t;
(pi*(D^2) /4)*Crushing stress = pi*D*t*(Crushing stress/4).
===> D=t;
Ashok kumar Chauhan said:
10 years ago
Shear stress = F/pi*d*t.
Crushing stress = 4F/pi*d^2.
Here pi = 22/7.
According to question Shear stress = Crushing stress/4.
That is why d = t.
Crushing stress = 4F/pi*d^2.
Here pi = 22/7.
According to question Shear stress = Crushing stress/4.
That is why d = t.
AMAL said:
10 years ago
Here a hole is punched then we need to take area of that hole that is (in shear) pi*d^2/4 and in crushing pi*d*t. So the right answer is d=t.
Prashant said:
9 years ago
Shear stress * 4 = crushing stress.
(F/pi * d * t) * 4 = (4F/pi * d * d).
therefore, d = t.
(F/pi * d * t) * 4 = (4F/pi * d * d).
therefore, d = t.
Sarath t r said:
9 years ago
Anybody. please help me. Actually what is the equation of crushing stress and how it came?
Praveen said:
9 years ago
@Sarath.
Crushing stress = f\crushing area.
Crushing area = pi * d * d/4.
Crushing stress = f\crushing area.
Crushing area = pi * d * d/4.
Mukesh said:
9 years ago
1/4 s.s = c.s
1/4 * F/pi d t = F/pi d d.
d = 4t.
1/4 * F/pi d t = F/pi d d.
d = 4t.
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