Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 3 (Q.No. 37)
37.
The relation between Young's modulus (E), shear modulus (C) and bulk modulus (K) is given by
Discussion:
2 comments Page 1 of 1.
Pelu said:
3 years ago
E=2c(1+v) ----> (i).
E=3k(1-2v) ----> (ii).
From (i),
V=(E/2C)-1.
From (ii);
E= 3k ( 1- 2(putting the value of v )).
Solving the eq;
E/K + 3E/C =9.
Or, 9KC = EG+3Ek.
Or , k = 9kc/ 3k+c
Hence solved.
E=3k(1-2v) ----> (ii).
From (i),
V=(E/2C)-1.
From (ii);
E= 3k ( 1- 2(putting the value of v )).
Solving the eq;
E/K + 3E/C =9.
Or, 9KC = EG+3Ek.
Or , k = 9kc/ 3k+c
Hence solved.
Phoring said:
7 years ago
E=2c(1+v).......(i).
E=3k(1-2v)........(ii).
From (i),
V=(E/2C)-1.
From (ii)
E= 3k ( 1- 2(putting the value of v )).
Solving the eq,
E/K + 3E/C =9.
Or, 9KC = EG+3Ek.
Or , k = 9kc/ 3k+c
Hence ..showed.
E=3k(1-2v)........(ii).
From (i),
V=(E/2C)-1.
From (ii)
E= 3k ( 1- 2(putting the value of v )).
Solving the eq,
E/K + 3E/C =9.
Or, 9KC = EG+3Ek.
Or , k = 9kc/ 3k+c
Hence ..showed.
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