Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 4 (Q.No. 14)
14.
The ratio of bulk modulus to Young's modulus for a Poisson's ratio of 0.25 will be
Discussion:
12 comments Page 1 of 2.
Nivetha said:
3 years ago
How to find k=1.5? Please explain.
Akash said:
4 years ago
K/E.
Keep K as it is K.
Apply E formula.
E = 3k(1-2m)=3k(1-2*2.5) = 1.5K.
K/E = k/1.5K = 1/1.5 = 2/3.
Keep K as it is K.
Apply E formula.
E = 3k(1-2m)=3k(1-2*2.5) = 1.5K.
K/E = k/1.5K = 1/1.5 = 2/3.
Naga said:
4 years ago
@Rajesh.
Poisson ratio(Mu) = 1/m,
0.25 = 1/m,
m = 1/0.25*10/10,
m = 100/25,
So, m = 4.
Poisson ratio(Mu) = 1/m,
0.25 = 1/m,
m = 1/0.25*10/10,
m = 100/25,
So, m = 4.
Numan khan said:
5 years ago
K/e = 0.667 = 2/3 How it came? Can anyone explain.
Rajesh said:
5 years ago
How to find m?
Yogendra Singh Chouhan said:
6 years ago
Relation Between Bulk Modulas & YoungModulas is K= mE/3(m-2).
(Where K= bulk modulas, E= Young Modulas, Poison Ratio 1/m = 0.25 Given So m= 4).
So Put M Value in Equation K= 4E/ 3(4-2).
K/E = 4/6.
K/E= 2/3.
(Where K= bulk modulas, E= Young Modulas, Poison Ratio 1/m = 0.25 Given So m= 4).
So Put M Value in Equation K= 4E/ 3(4-2).
K/E = 4/6.
K/E= 2/3.
(1)
Srilakshmi said:
7 years ago
The relation b/w E & K is E=3K(1-2*MU).
E = 3K(1-2*0.25),
E = K * 1.5,
1/1.5 = K/E,
1*10/15 = K/E,
2/3 = K/E.
E = 3K(1-2*0.25),
E = K * 1.5,
1/1.5 = K/E,
1*10/15 = K/E,
2/3 = K/E.
CHANDRESH KALSARIYA said:
7 years ago
How to find this formula?
Please explain.
Please explain.
Ppradeep gk said:
8 years ago
Here, E=3k (1-2u).
PRATIK said:
1 decade ago
E = 3K(1-2U).
E/K = 1/1.5.
E/K = 0.667 = 2/3.
E/K = 1/1.5.
E/K = 0.667 = 2/3.
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