Mechanical Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 4 (Q.No. 21)
21.
A bar of copper and steel form a composite system, which is heated to a temperature of 40°C. The stress induced in the copper bar will be
tensile
compressive
shear
zero
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
9 comments Page 1 of 1.

Er.Sam said:   6 years ago
It's due to to bonding between more stronger material like steel. They are not free to expand. So stresses developed will be of compressive in nature.

Eswar mareedu said:   6 years ago
Coefficient of thermal expansion of copper is more then steel and strength of steel is more compare to copper so copper should try to overcome the strength of steel but strength of steel not allow to elongation of copper results copper is under compression assume both are tight together.

Vickey Sharma said:   6 years ago
This is composite bar ie overlapping of steel and copper. Now the thermal expansion of copper is more than steel so copper expands (tension) at the same time steel (compress).

Julius said:   7 years ago
@Rohan.

Your explanation is very clear. Thanks a lot.

Mano said:   8 years ago
Good explanation thank you all.

Heisenberg said:   9 years ago
The thermal coefficient of linear expansion of copper is more so its expansion is suppressed so compressed.

Rohan said:   9 years ago
Assuming they are bonded over another and fixed at one end since the coefficient of thermal expansion for copper is more than steel. Copper will try to pull steel since they are the composite system in that sense copper will be subjected to compression and steel to tensile.
(1)

Kiran said:   10 years ago
Since there is not mentioned that whether the bar freely expand or fixed at both ends so can not predict which stress is developed.

Dhiru said:   1 decade ago
Copper - compressive.

Steel - tensile stress.

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