Mechanical Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 9 (Q.No. 38)
38.
The shear modulus of most materials with respect to the modulus of elasticity is
equal to half
less than half
more than half
none of these
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
18 comments Page 1 of 2.

AMIT Singh said:   4 years ago
E=2G(1+ posion ratio).
Example, for steel E =210Gpa,
And poison ratio up to . 33.
210= 2G (1+.33)= G= 78.94 so G is less than 1/2 of E (210GPa).
(2)

Mohit Choudhary said:   4 years ago
Please give an explanation.

Abhay Patel said:   5 years ago
I am not understanding please describe me clearly.

Vinitha said:   5 years ago
I don't understand please explain.

Karan Panjabi said:   5 years ago
@Anidhya.

Correct relationship between Young's Modulus with shear modulus and with Young's Modulus and bulk modulus.

Deepak Dhami said:   5 years ago
We know,
E = 2N(1+u).
>N = (E/2)*(1/(1+u)).
Where, (1+u)~1.
Hence, N = E/2.

Prasad said:   6 years ago
G is shear modulus.
E is elasticity modulus.

E=2G(1+Poisson's ratio)
Then G=E/2*(1+Poisson's ratio).

Substitution the value in the above equation and result will be less than half.

Paramveer said:   7 years ago
I Can't understand. Please, someone, explain me.

Anidhya said:   7 years ago
E = 2G ( 1+u).
E = 3k ( 1-2u).

CPV said:   8 years ago
E = 2G ( 1+u)
E = 2k ( 1-2u)
Where :- u - poisons ratio.
K - bulk modulus
G- rigidity modulus.
E- modulus of elasticity.


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