Mechanical Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 4 (Q.No. 13)
13.
The extension of a circular bar tapering uniformly from diameter d1 at one end to diameter d2 at the other end, and subjected to an axial pull of P is given by
Discussion:
2 comments Page 1 of 1.
Ramanath said:
6 years ago
Delta - PL/AE,
A is equal to pi/4 into d1*d2.
A is equal to pi/4 into d1*d2.
Harish said:
9 years ago
E = Stress/Strain,
Stress = Force/area,
E * Strain = Force/area.
Now solve you will get Option C.
Stress = Force/area,
E * Strain = Force/area.
Now solve you will get Option C.
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