Mechanical Engineering - Steam Nozzles and Turbines - Discussion
Discussion Forum : Steam Nozzles and Turbines - Section 3 (Q.No. 15)
15.
In a Parson's turbine stage, blade velocity is 320 m/s at the mean radius and rotor blade exit angle is 30°. For minimum kinetic energy of the steam leaving the stage, the steam velocity at the exit of the rotor will be
Discussion:
6 comments Page 1 of 1.
Raju said:
8 years ago
Explain the answer clearly.
(1)
Tapan majumder said:
1 decade ago
Blade velocity = v(1)*cos(alpfa).
v1 = steam velocity at the exit of the nozzle.
v1 = 320/cos(30) = 640/(root3).
v1 = steam velocity at the exit of the nozzle.
v1 = 320/cos(30) = 640/(root3).
Abhi said:
8 years ago
U/v = cos α for reaction turbine (parson).
Rupesh said:
7 years ago
u/v=cos α so u has value 320; α= 30.
320/v= cos 30.
V=640/√3.
320/v= cos 30.
V=640/√3.
Nitesh Bharti said:
5 years ago
Here it is said that exit velocity of rotor, not nozzle so Option B is correct.
Biprojit said:
5 years ago
Stream velocity at exit of rotor =Vr (2) = V1 and vane angle at outlet = inlet nozzle angle according to conditions of 50% rxn turbine.
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