# Mechanical Engineering - Steam Nozzles and Turbines - Discussion

### Discussion :: Steam Nozzles and Turbines - Section 3 (Q.No.15)

15.

In a Parson's turbine stage, blade velocity is 320 m/s at the mean radius and rotor blade exit angle is 30°. For minimum kinetic energy of the steam leaving the stage, the steam velocity at the exit of the rotor will be

 [A]. 160/3 m/s [B]. 320/3 m/s [C]. 640/3 m/s [D]. 640 m/s

Explanation:

No answer description available for this question.

 Tapan Majumder said: (Nov 28, 2013) Blade velocity = v(1)*cos(alpfa). v1 = steam velocity at the exit of the nozzle. v1 = 320/cos(30) = 640/(root3).

 Abhi said: (Jul 27, 2017) U/v = cos α for reaction turbine (parson).

 Raju said: (Sep 19, 2017) Explain the answer clearly.

 Rupesh said: (Dec 9, 2018) u/v=cos α so u has value 320; α= 30. 320/v= cos 30. V=640/√3.

 Nitesh Bharti said: (Apr 11, 2020) Here it is said that exit velocity of rotor, not nozzle so Option B is correct.

 Biprojit said: (Apr 25, 2020) Stream velocity at exit of rotor =Vr (2) = V1 and vane angle at outlet = inlet nozzle angle according to conditions of 50% rxn turbine.