Mechanical Engineering - Production Engineering - Discussion
Discussion Forum : Production Engineering - Section 7 (Q.No. 1)
1.
A drill bit of 20 mm diameter rotating at 500 r.p.m. with a feed rate of 0.2 mm/revolution is used to drill a through-hole in a mild steel plate 20 mm thickness. The depth of cut in this drilling operation is
Discussion:
26 comments Page 3 of 3.
Mohan kumar said:
6 years ago
What is the depth of cut in drilling?
Depth of cut is half the diameter of drill diameter. Right? Please explain.
Depth of cut is half the diameter of drill diameter. Right? Please explain.
Chaitanya said:
6 years ago
Given that d =20mm.
T =20mm.
D2 = 2T+ D1(hollow)
D2 = 60.
We know that D2-D1/2 is the formulae.
So answer is 60-20/2.
= 20mm.
T =20mm.
D2 = 2T+ D1(hollow)
D2 = 60.
We know that D2-D1/2 is the formulae.
So answer is 60-20/2.
= 20mm.
(4)
Vinay said:
5 years ago
Given 20mm is the right answer.
(1)
Roshan said:
5 years ago
Please can anybody tell what is the right answer?
Krishna said:
4 years ago
Which is correct?
20 or 10 mm, Please explain.
20 or 10 mm, Please explain.
Sami tefera said:
1 year ago
The depth of cut in this drilling operation can be calculated by multiplying the feed rate (0.2 mm/revolution) by the number of revolutions required to drill through the entire thickness of the mild steel plate (20 mm).
To find the number of revolutions, we can divide the thickness of the plate (20 mm) by the feed rate (0.2 mm/revolution):
Number of revolutions = Thickness of plate/Feed rate.
Number of revolutions = 20 mm/0.2 mm/revolution.
Number of revolutions = 100 revolutions.
Therefore, the correct answer is d. 100 mm.
To find the number of revolutions, we can divide the thickness of the plate (20 mm) by the feed rate (0.2 mm/revolution):
Number of revolutions = Thickness of plate/Feed rate.
Number of revolutions = 20 mm/0.2 mm/revolution.
Number of revolutions = 100 revolutions.
Therefore, the correct answer is d. 100 mm.
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