Mechanical Engineering - Machine Design - Discussion
Discussion Forum : Machine Design - Section 3 (Q.No. 48)
48.
When the speed of belt increases,
Discussion:
18 comments Page 1 of 2.
Manoj said:
1 decade ago
p = (T1-T2)*v.
So if speed increases, power transmitted should also increase.
So if speed increases, power transmitted should also increase.
Gaurav said:
1 decade ago
Power = Torque*w.
Correct answer is D.
Correct answer is D.
VENKATESH said:
10 years ago
No, Power = (Torque x Velocity)/33000 hp.
Hence 'C' is correct.
Hence 'C' is correct.
Sampad bera said:
9 years ago
I think correct answer will be D, because p = (t1 - t2) * v.
Sampad bera said:
9 years ago
I think correct answer will be D, because p = (t1 - t2) * v.
Nomaan ahmad khan said:
8 years ago
Yes, the Answer is d.
Vaseem said:
8 years ago
The answer is C. Because at the higher speed the belt slips on the pulley and so the power will be less as compared to desired power at corresponding speed (as in ideal condition). If the belt doesn't slip on the pulley at a higher speed then the power will increase. But it is not possible in actual practice.
Rahil said:
8 years ago
When the speed got increased then the sliping also increase so the power transmission got decrease.
Pavan kumar chilakala said:
7 years ago
According to the formula, power transmission should increase but as in actual practice that is impossible without slip.
(1)
AZMAL MALLICK said:
7 years ago
C is correct, practically speed increases than slip increases and so power decrease.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers