Mechanical Engineering - Machine Design - Discussion
Discussion Forum : Machine Design - Section 4 (Q.No. 6)
6.
A circular shaft can transmit a torque of 5 kN-m. If the torque is reduced to 4 kN-m, then the maximum value of bending moment that can be applied to the shaft is
Discussion:
14 comments Page 1 of 2.
Gaurav said:
1 decade ago
How 3 kN-m?
Engineer Abdul baqi said:
1 decade ago
In this equation if you people said me the using formula only send me using formula of this equation.
Zuhaib said:
1 decade ago
Send me formula dear.
Getaneh said:
10 years ago
What is the formula?
Sayad nasim said:
10 years ago
Hello dear one, formula is:
T(equivalent) = sqrt root (T^2+M^2).
=> 5^2 = sqrt root (4^2+M^2).
=> M = 3.
T(equivalent) = sqrt root (T^2+M^2).
=> 5^2 = sqrt root (4^2+M^2).
=> M = 3.
Sayad nasim said:
10 years ago
T (equivalent) = sqrt root (M^2+T^2).
Tulu said:
9 years ago
We know that
T = √ T^2 + √ M^2.
From this formula, we found that M = 3Knm.
T = √ T^2 + √ M^2.
From this formula, we found that M = 3Knm.
Shankar B C said:
8 years ago
Nice explanations. Thanks.
Jayram chauhan said:
8 years ago
Thanks for the explanation.
Jayrald said:
7 years ago
Thank you all for explaining.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers