Mechanical Engineering - Machine Design - Discussion
Discussion Forum : Machine Design - Section 4 (Q.No. 6)
6.
A circular shaft can transmit a torque of 5 kN-m. If the torque is reduced to 4 kN-m, then the maximum value of bending moment that can be applied to the shaft is
Discussion:
14 comments Page 2 of 2.
Khushi said:
6 years ago
Thanks for explaining the answer.
Akshay Sankpal said:
5 years ago
If torque is not reduced then there will be no bending moment, Right?
Manish said:
5 years ago
@All.
Acc. to question there should be some relation between bending moment and torque, we can't equate it to equivalent torque, as it states that it can transfer torque of 5kN-m and if this torque is reduced, then the value of bending moment is what, this means there should lie a value of bending moment when the torque is 5kNm and when we reduce the torque to 4kNm what will be the value of bending moment. so it can't be equated to equivalent torque equation, in another way if we equate the max. bending equals to the max. shear, then we can get a linear relation between bending moment and torque. as T=2M, so this can be used in this question, so the answer would have been 2kNm.
At T=5,M=2.5
at T=4, M=2
Acc. to question there should be some relation between bending moment and torque, we can't equate it to equivalent torque, as it states that it can transfer torque of 5kN-m and if this torque is reduced, then the value of bending moment is what, this means there should lie a value of bending moment when the torque is 5kNm and when we reduce the torque to 4kNm what will be the value of bending moment. so it can't be equated to equivalent torque equation, in another way if we equate the max. bending equals to the max. shear, then we can get a linear relation between bending moment and torque. as T=2M, so this can be used in this question, so the answer would have been 2kNm.
At T=5,M=2.5
at T=4, M=2
(1)
Ganeshr said:
4 years ago
@Sayad Nadeem.
Correct explanation. Thanks.
Correct explanation. Thanks.
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