Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 1 (Q.No. 10)
10.
An error of 1% in measuring head over the apex of the notch (H) will produce an error of __________ in discharge over a triangular notch.
Discussion:
15 comments Page 1 of 2.
Kjis said:
8 years ago
Just differenciate q=kh^5/2.
dq=k5/2dh-----equation(1)
Assume constant k=1
From given data dh=1%
Put above value in equation (1).
So dq=(1) *(5/2)*(1).
dq=5/2=2.5%.
dq=k5/2dh-----equation(1)
Assume constant k=1
From given data dh=1%
Put above value in equation (1).
So dq=(1) *(5/2)*(1).
dq=5/2=2.5%.
(1)
Asdfg said:
1 decade ago
Q = K*H^2.5.
On taking logarithm on both sides we get.
ln Q = ln K+2.5*lnH.
Now on differentiating the both sides we get the answer.
On taking logarithm on both sides we get.
ln Q = ln K+2.5*lnH.
Now on differentiating the both sides we get the answer.
Victor said:
9 years ago
@Harsha Kalluri.
H = Height of the liquid above the apex of the notch.
k = Constant.
Q = Discharge over the notch.
H = Height of the liquid above the apex of the notch.
k = Constant.
Q = Discharge over the notch.
Sunil said:
7 years ago
@Learner.
H = Height of the liquid above the apex of the notch.
k = Constant.
Q = Discharge over the notch.
H = Height of the liquid above the apex of the notch.
k = Constant.
Q = Discharge over the notch.
Rakesh bharti said:
1 decade ago
Q = kh^5/2.
Differential on both side.
dQ = 5/2kh^3/2dh.
Divide to Q on both side.
dQ/Q = 5dh/h.
Differential on both side.
dQ = 5/2kh^3/2dh.
Divide to Q on both side.
dQ/Q = 5dh/h.
S. Ata said:
8 years ago
To calculate discharge Multiple the head error by:-
2.5(triangular notch).
1.5(rectangular notch).
2.5(triangular notch).
1.5(rectangular notch).
(3)
Praveen said:
1 decade ago
DISCHARGE Q = kH^5/2.
DIFFERENTIATE IT, WE GET-dQ = 5/2*kH^3/2*dH.
NOW DIVIDE-dQ/Q = 5/2*dH/H.
DIFFERENTIATE IT, WE GET-dQ = 5/2*kH^3/2*dH.
NOW DIVIDE-dQ/Q = 5/2*dH/H.
Harsha Kalluri said:
9 years ago
I want to know how the equation Q = kh^5/2 is formed? and what is k, h and Q.
Please tell me.
Please tell me.
Nithin John Simon said:
3 years ago
For Triangular Notch:
dQ/Q = (5/2) * dH/H.
For Rectangular Notch:
dQ/Q = (3/2) * dH/H.
dQ/Q = (5/2) * dH/H.
For Rectangular Notch:
dQ/Q = (3/2) * dH/H.
(6)
Sagar said:
10 years ago
Guys, I want to know, what is measuring head & what is notch. Could you tell me?
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