Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 5 (Q.No. 34)
34.
The height of a water column equivalent to a pressure of 0.15 MPa is
Discussion:
5 comments Page 1 of 1.
Zaheer ali said:
5 years ago
p = wh.
h = p/w,
h = 0.15 * 10^6/9.81 * 10^3.
h = 15.3m.
h = p/w,
h = 0.15 * 10^6/9.81 * 10^3.
h = 15.3m.
(2)
Raam said:
6 years ago
P = rho*g*h
We need only h(metre).
So divide pressure value by rho*g.
Mpa = 10^6 *N/m^2.
We need only h(metre).
So divide pressure value by rho*g.
Mpa = 10^6 *N/m^2.
Shubham Dongarkar said:
7 years ago
It can be solved by comparing,
As 1atm pressure = 101.3kpa = 0.1013mpa which cause 10.3m of water rise
And thus,
0.1013mpa=10.3m,
0.15mpa=X,
X=10.3 x 0.15/0.1013.
X=15.2517m.
As 1atm pressure = 101.3kpa = 0.1013mpa which cause 10.3m of water rise
And thus,
0.1013mpa=10.3m,
0.15mpa=X,
X=10.3 x 0.15/0.1013.
X=15.2517m.
Pradeep gk said:
8 years ago
We know that 10.3m = 1.01325*10^5 pa,
X = 0.15*10^6 pa.
Cross multiple we will get the answer X=15.2m.
X = 0.15*10^6 pa.
Cross multiple we will get the answer X=15.2m.
JANA said:
1 decade ago
p = H*W.
p = 0.15 * 10^6 pa.
w = specific weight of water = 9810 N/m3.
i.e., H = (0.15 * 10^6)/(9810) = 15.3 m.
p = 0.15 * 10^6 pa.
w = specific weight of water = 9810 N/m3.
i.e., H = (0.15 * 10^6)/(9810) = 15.3 m.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers