Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 3 (Q.No. 10)
10.
With an increase in size of tube, the rise or depression of liquid in the tube due to surface tension will
Discussion:
8 comments Page 1 of 1.
Shashikant Rai said:
6 years ago
@Rahu.
Due to capillary action the rise or fall of liquid in a tube is calculated by the formula.
h = ( 2*t*cosY)/(Ï*g*r) or = ( 4*t*cosY)/(w*d).
Therefore h is inversely proportional to d.
Due to capillary action the rise or fall of liquid in a tube is calculated by the formula.
h = ( 2*t*cosY)/(Ï*g*r) or = ( 4*t*cosY)/(w*d).
Therefore h is inversely proportional to d.
(1)
Rana Dhaval said:
10 years ago
h = 4q cosQ/ 2gd. So h is inversely proportional to d.
Rajkumar Nayak said:
10 years ago
h = 4*t*cos (x)/wd, where, keeping all term constant.
We can say that rise or fall is inversely proportional to dia of tube.
We can say that rise or fall is inversely proportional to dia of tube.
Kishan Ahir said:
7 years ago
D is inverlsly propositional to H.
Jai said:
7 years ago
h=4 * ρ 8cosq/wd.
ρ(surface tension) is directly proportional to d.
So, the surface tension increases.
ρ(surface tension) is directly proportional to d.
So, the surface tension increases.
Rahu said:
6 years ago
How? Please explain in clear.
Kataiah sajja said:
6 years ago
Units of surface tension is N/m, so surface tension is inversaly proportional to the diameter of tube. The diameter mentioned in m, mm, cm etc.
Velmurugan R said:
6 years ago
P = (4*Σ)/d.
P is inversely proportional to the diameter
P is inversely proportional to the diameter
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers