Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion

10. 

With an increase in size of tube, the rise or depression of liquid in the tube due to surface tension will

[A]. decrease
[B]. increase
[C]. remain unchanged
[D]. depend upon the characteristics of liquid

Answer: Option A

Explanation:

No answer description available for this question.

Rana Dhaval said: (Nov 26, 2015)  
h = 4q cosQ/ 2gd. So h is inversely proportional to d.

Rajkumar Nayak said: (Feb 11, 2016)  
h = 4*t*cos (x)/wd, where, keeping all term constant.

We can say that rise or fall is inversely proportional to dia of tube.

Kishan Ahir said: (Apr 13, 2018)  
D is inverlsly propositional to H.

Jai said: (Jan 7, 2019)  
h=4 * ρ 8cosq/wd.
ρ(surface tension) is directly proportional to d.
So, the surface tension increases.

Rahu said: (Jun 30, 2019)  
How? Please explain in clear.

Kataiah Sajja said: (Aug 1, 2019)  
Units of surface tension is N/m, so surface tension is inversaly proportional to the diameter of tube. The diameter mentioned in m, mm, cm etc.

Velmurugan R said: (Aug 29, 2019)  
P = (4*Σ)/d.

P is inversely proportional to the diameter

Shashikant Rai said: (Sep 6, 2019)  
@Rahu.

Due to capillary action the rise or fall of liquid in a tube is calculated by the formula.

h = ( 2*t*cosY)/(ρ*g*r) or = ( 4*t*cosY)/(w*d).

Therefore h is inversely proportional to d.

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