# Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion

10.

With an increase in size of tube, the rise or depression of liquid in the tube due to surface tension will

 [A]. decrease [B]. increase [C]. remain unchanged [D]. depend upon the characteristics of liquid

Explanation:

No answer description available for this question.

 Rana Dhaval said: (Nov 26, 2015) h = 4q cosQ/ 2gd. So h is inversely proportional to d.

 Rajkumar Nayak said: (Feb 11, 2016) h = 4*t*cos (x)/wd, where, keeping all term constant. We can say that rise or fall is inversely proportional to dia of tube.

 Kishan Ahir said: (Apr 13, 2018) D is inverlsly propositional to H.

 Jai said: (Jan 7, 2019) h=4 * ρ 8cosq/wd. ρ(surface tension) is directly proportional to d. So, the surface tension increases.

 Rahu said: (Jun 30, 2019) How? Please explain in clear.

 Kataiah Sajja said: (Aug 1, 2019) Units of surface tension is N/m, so surface tension is inversaly proportional to the diameter of tube. The diameter mentioned in m, mm, cm etc.

 Velmurugan R said: (Aug 29, 2019) P = (4*Σ)/d. P is inversely proportional to the diameter

 Shashikant Rai said: (Sep 6, 2019) @Rahu. Due to capillary action the rise or fall of liquid in a tube is calculated by the formula. h = ( 2*t*cosY)/(ρ*g*r) or = ( 4*t*cosY)/(w*d). Therefore h is inversely proportional to d.