Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 5 (Q.No. 22)
22.
The kinematic viscosity of an oil (in stokes) whose specific gravity is 0.95 and viscosity 0.011 poise, is
Discussion:
14 comments Page 2 of 2.
Saurabh Kumar said:
8 years ago
Please explain throughly.
Hirang said:
8 years ago
The correct answer is B.
0.011 = 110 * 10^-4.
0.011 = 110 * 10^-4.
Teja said:
8 years ago
Nice description. Thanks.
JANA said:
1 decade ago
Dynamic viscosity = 0.011 poise.
1 poise = 0.1 Ns/m2. 1N = 1kg m/s2.
i.e., 1 poise = 0.1 kg/ms.
Specific gravity = density of liquid/density of water.
Density of water = 1000 kg/m3. sp.gravity = 0.95.
So, 0.95 = density/1000.
i.e., density = 950 kg/m3.
Kinematic viscosity = dynamic viscosity/density.
K.V = 11*10^-4/950. (1 stoke = 10^-4 m2/s).
So, K.V = 0.0116 stokes.
1 poise = 0.1 Ns/m2. 1N = 1kg m/s2.
i.e., 1 poise = 0.1 kg/ms.
Specific gravity = density of liquid/density of water.
Density of water = 1000 kg/m3. sp.gravity = 0.95.
So, 0.95 = density/1000.
i.e., density = 950 kg/m3.
Kinematic viscosity = dynamic viscosity/density.
K.V = 11*10^-4/950. (1 stoke = 10^-4 m2/s).
So, K.V = 0.0116 stokes.
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