Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion

Discussion Forum : Hydraulics and Fluid Mechanics - Section 7 (Q.No. 21)
21.
The total pressure on the top of a closed cylindrical vessel competely filled up with a liquid is
directly proportional to (radius)2
inversely proportional to (radius)2
directly proportional to (radius)4
inversely proportional to (radius)4
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
16 comments Page 1 of 2.

Rajesh Rar said:   8 years ago
@Ajaypal.

If total pressure =pressure*area.
The Unit will become as N/mm4.
(1)

Mizanur said:   7 years ago
Thanks @Ajaypal.
(1)

Ganesh said:   6 years ago
@Ajaypal.

Here m^2 and m^2 will be cancelled. It should not be multiply.
(1)

Muhammad Azkar said:   6 years ago
The total pressure on the top of the liquid-filled cylindrical vessel is given by -

P = π.W.ω^2.r^2 / 4.g

As we know, W = V x ρ = πr^2h.ρ

P = π.πr^2h.ρ.ω^2.r^2 / 4.g

P = π^2.h.ρ.ω^2.r^4 / 4.g

P ∝ r^4

C is the correct answer.
(1)

Amit kumar said:   9 years ago
Option A will be the correct Answer.

Karan said:   9 years ago
Option A will be the correct answer. Because the pressure, P = π * W * w2 * r2/4g.

Vinash ka devta said:   9 years ago
C is right.

Because, w=area * height.

Ahlawat said:   8 years ago
Option A is correct, w is not volume it is a specific weight which is density * s.g.

Minesh Rathore said:   8 years ago
A is correct because P = (density * w2 * r2)/2.

Ajaypal said:   8 years ago
Option C is correct because " Total Pressure "(and not pressure) has been asked which means Force on Area [&pie;*r^2].

So, Total pressure = Pressure * Area.
And hence Total pressure is proportional to r^4.


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