Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 7 (Q.No. 21)
21.
The total pressure on the top of a closed cylindrical vessel competely filled up with a liquid is
Discussion:
16 comments Page 1 of 2.
Amit kumar said:
9 years ago
Option A will be the correct Answer.
Karan said:
9 years ago
Option A will be the correct answer. Because the pressure, P = π * W * w2 * r2/4g.
Vinash ka devta said:
9 years ago
C is right.
Because, w=area * height.
Because, w=area * height.
Ahlawat said:
8 years ago
Option A is correct, w is not volume it is a specific weight which is density * s.g.
Minesh Rathore said:
8 years ago
A is correct because P = (density * w2 * r2)/2.
Ajaypal said:
8 years ago
Option C is correct because " Total Pressure "(and not pressure) has been asked which means Force on Area [&pie;*r^2].
So, Total pressure = Pressure * Area.
And hence Total pressure is proportional to r^4.
So, Total pressure = Pressure * Area.
And hence Total pressure is proportional to r^4.
Rajesh Rar said:
8 years ago
@Ajaypal.
If total pressure =pressure*area.
The Unit will become as N/mm4.
If total pressure =pressure*area.
The Unit will become as N/mm4.
(1)
Anirudha said:
7 years ago
It is πww^2r^4/4g.
Mizanur said:
7 years ago
Thanks @Ajaypal.
(1)
Ganesh said:
6 years ago
@Ajaypal.
Here m^2 and m^2 will be cancelled. It should not be multiply.
Here m^2 and m^2 will be cancelled. It should not be multiply.
(1)
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