Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 1 (Q.No. 6)
6.
The diameter of the nozzle (d) for maximum transmission of power is given by (where D = Diameter of pipe, f = Darcy 's coefficient of friction for pipe, and l = Length of pipe )
Discussion:
36 comments Page 2 of 4.
Dhaval said:
8 years ago
Q=aV,a=Area V=velocity I think now you get @Siddu Gd Karagi.
Siddu GD karagi said:
8 years ago
I am not getting it please give me a brief explanation.
Johnson said:
8 years ago
Explain the derivation please.
Harsha said:
8 years ago
Nice explanation @Sia.
(1)
Sia said:
8 years ago
For maximum transmission, H=3h,
where H=Total Supply Head,
h=head lost due to friction,
H=3h.
=>v^2/2g=3 flV^2/(2gD),
where, v=velocity at the nozzle end,
V=velocity in pipe.
=>Q^2/(a^2.2g)=3flQ^2/(A^2/2gD).
where a=nozzle area,
A=area of pipe,
=>3fld^4=D^5.
=>d= (D^5/(3fl))^(1/4).
where H=Total Supply Head,
h=head lost due to friction,
H=3h.
=>v^2/2g=3 flV^2/(2gD),
where, v=velocity at the nozzle end,
V=velocity in pipe.
=>Q^2/(a^2.2g)=3flQ^2/(A^2/2gD).
where a=nozzle area,
A=area of pipe,
=>3fld^4=D^5.
=>d= (D^5/(3fl))^(1/4).
(1)
Tushar said:
8 years ago
Please give explanation.
Anju said:
8 years ago
Please explain the answer of this question.
Monex sharma said:
9 years ago
Solve using dimensional method.
=> f is unit less.
=> D^5/l has dimension L^4.
=> f is unit less.
=> D^5/l has dimension L^4.
Ritu singh said:
9 years ago
Explain it properly (stepwise).
Bharat said:
9 years ago
It will be 2fl in place of 8fl.
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