Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion

Discussion Forum : Hydraulics and Fluid Mechanics - Section 1 (Q.No. 6)
6.
The diameter of the nozzle (d) for maximum transmission of power is given by (where D = Diameter of pipe, f = Darcy 's coefficient of friction for pipe, and l = Length of pipe )
Answer: Option
Explanation:
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Discussion:
36 comments Page 1 of 4.

Leela Krishna said:   5 years ago
Explain the full step, please.
(1)

Sia said:   8 years ago
For maximum transmission, H=3h,
where H=Total Supply Head,
h=head lost due to friction,
H=3h.
=>v^2/2g=3 flV^2/(2gD),
where, v=velocity at the nozzle end,
V=velocity in pipe.
=>Q^2/(a^2.2g)=3flQ^2/(A^2/2gD).
where a=nozzle area,
A=area of pipe,
=>3fld^4=D^5.
=>d= (D^5/(3fl))^(1/4).
(1)

Tilak said:   6 years ago
The answer is (d^5/2fl)^1/4 where f is darcy friction factor. After correcting a step in @Sia's answer,

V^2/2g = 2 hf = 2 flV^2/ (2gD).
(1)

Durga Prasad said:   6 years ago
@Sia.

Instead of 8fl you mention 3fl, which is the correct formula? Please explain.
(1)

Harsha said:   8 years ago
Nice explanation @Sia.
(1)

Anju said:   8 years ago
Please explain the answer of this question.

Monex sharma said:   8 years ago
Solve using dimensional method.

=> f is unit less.
=> D^5/l has dimension L^4.

Tushar said:   8 years ago
Please give explanation.

Johnson said:   8 years ago
Explain the derivation please.

Siddu GD karagi said:   8 years ago
I am not getting it please give me a brief explanation.


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