Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion
Discussion Forum : Hydraulics and Fluid Mechanics - Section 2 (Q.No. 1)
1.
A compound pipe of diameter d1, d2 and d3 having lengths l1, l2 and l3 is to be replaced by an equivalent pipe of uniform diameter d and of the same length (l) as that of the compound pipe. The size of the equivalent pipe is given by
Discussion:
6 comments Page 1 of 1.
Taher said:
5 years ago
Above equation is for parallel pipes.
Karthick said:
7 years ago
Is above formulae used for pipes in parallel as well?
(1)
Hari said:
7 years ago
Fluid entering is equal to fluid exit, i.e discharge remains constant, so apply the equation of discharge and arrange it.
Pranav said:
10 years ago
For '1, 2, 3,....N' pipes, having 'L1, L2, L3,....Ln' lengths & 'd1, d2, d3,....dn' dia. In order to replaced by single pipe of L & D length & dia resp.
L/D^5 = (l1/d1^5)+(l2/d2^5)+(l3/d3^5)+.....(ln/dn^5).
L/D^5 = (l1/d1^5)+(l2/d2^5)+(l3/d3^5)+.....(ln/dn^5).
(1)
Poonam said:
1 decade ago
If there have many pipes. Than what will be answer?
(1)
Gowtham said:
1 decade ago
The discharge will be same and by the equation q=4flv^2/d^5 we get answer.
(1)
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