Mechanical Engineering - Hydraulics and Fluid Mechanics - Discussion


A compound pipe of diameter d1, d2 and d3 having lengths l1, l2 and l3 is to be replaced by an equivalent pipe of uniform diameter d and of the same length (l) as that of the compound pipe. The size of the equivalent pipe is given by


Answer: Option D


No answer description available for this question.

Gowtham said: (Oct 6, 2013)  
The discharge will be same and by the equation q=4flv^2/d^5 we get answer.

Poonam said: (Jan 8, 2014)  
If there have many pipes. Than what will be answer?

Pranav said: (Oct 5, 2015)  
For '1, 2, 3,....N' pipes, having 'L1, L2, L3,....Ln' lengths & 'd1, d2, d3,....dn' dia. In order to replaced by single pipe of L & D length & dia resp.

L/D^5 = (l1/d1^5)+(l2/d2^5)+(l3/d3^5)+.....(ln/dn^5).

Hari said: (Apr 17, 2018)  
Fluid entering is equal to fluid exit, i.e discharge remains constant, so apply the equation of discharge and arrange it.

Karthick said: (Sep 27, 2018)  
Is above formulae used for pipes in parallel as well?

Taher said: (Jun 28, 2020)  
Above equation is for parallel pipes.

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