Mechanical Engineering - Hydraulic Machines - Discussion
Discussion Forum : Hydraulic Machines - Section 4 (Q.No. 6)
6.
A turbine develops 10000 kW under a head of 25 metres at 135 r.p.m. Its specific speed is
Discussion:
6 comments Page 1 of 1.
Sougata ghosh said:
9 years ago
I don't know, please help me.
SANTOSH KUMAR SAHU said:
8 years ago
As we know the specific speed of the turbine is given by;
N = N * Root P divided by H to the power 5/4.
So here we can get.
N = 135 * Root of 10000 Divided by 25 to the power 5/4.
N = 241.495 rpm => ANSWER.
N = N * Root P divided by H to the power 5/4.
So here we can get.
N = 135 * Root of 10000 Divided by 25 to the power 5/4.
N = 241.495 rpm => ANSWER.
Bhuppi said:
8 years ago
The thing to note here is that the power is entered in Kw and not in watts.
Kazzafi said:
8 years ago
Couldn't find the answer.
And explain how the unit will be in rpm?
And explain how the unit will be in rpm?
Sathish said:
7 years ago
N = 135 * Root of 10000 Divided by 25 to the power 5/4.
135*100/47.59
N=283.67.
135*100/47.59
N=283.67.
Roshan said:
5 years ago
The specific speed =N""p / H^5/4.
(speed*under root power ) divided by Head to the power of 5/4,
so (135*""10000) / 25^5/4,
= 241.49~241.5.
(speed*under root power ) divided by Head to the power of 5/4,
so (135*""10000) / 25^5/4,
= 241.49~241.5.
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