# Mechanical Engineering - Hydraulic Machines - Discussion

Discussion Forum : Hydraulic Machines - Section 4 (Q.No. 6)
6.
A turbine develops 10000 kW under a head of 25 metres at 135 r.p.m. Its specific speed is
175.4 r.p.m.
215.5 r.p.m.
241.5 r.p.m.
275.4 r.p.m
Explanation:
No answer description is available. Let's discuss.
Discussion:
6 comments Page 1 of 1.

Roshan said:   4 years ago
The specific speed =N""p / H^5/4.
(speed*under root power ) divided by Head to the power of 5/4,
so (135*""10000) / 25^5/4,
= 241.49~241.5.

Sathish said:   6 years ago
N = 135 * Root of 10000 Divided by 25 to the power 5/4.
135*100/47.59
N=283.67.

Kazzafi said:   7 years ago

And explain how the unit will be in rpm?

Bhuppi said:   7 years ago
The thing to note here is that the power is entered in Kw and not in watts.

SANTOSH KUMAR SAHU said:   8 years ago
As we know the specific speed of the turbine is given by;

N = N * Root P divided by H to the power 5/4.

So here we can get.

N = 135 * Root of 10000 Divided by 25 to the power 5/4.

N = 241.495 rpm => ANSWER.

Sougata ghosh said:   8 years ago