# Mechanical Engineering - Hydraulic Machines - Discussion

Discussion Forum : Hydraulic Machines - Section 4 (Q.No. 6)

6.

A turbine develops 10000 kW under a head of 25 metres at 135 r.p.m. Its specific speed is

Discussion:

6 comments Page 1 of 1.
Roshan said:
4 years ago

The specific speed =N""p / H^5/4.

(speed*under root power ) divided by Head to the power of 5/4,

so (135*""10000) / 25^5/4,

= 241.49~241.5.

(speed*under root power ) divided by Head to the power of 5/4,

so (135*""10000) / 25^5/4,

= 241.49~241.5.

Sathish said:
6 years ago

N = 135 * Root of 10000 Divided by 25 to the power 5/4.

135*100/47.59

N=283.67.

135*100/47.59

N=283.67.

Kazzafi said:
7 years ago

Couldn't find the answer.

And explain how the unit will be in rpm?

And explain how the unit will be in rpm?

Bhuppi said:
7 years ago

The thing to note here is that the power is entered in Kw and not in watts.

SANTOSH KUMAR SAHU said:
8 years ago

As we know the specific speed of the turbine is given by;

N = N * Root P divided by H to the power 5/4.

So here we can get.

N = 135 * Root of 10000 Divided by 25 to the power 5/4.

N = 241.495 rpm => ANSWER.

N = N * Root P divided by H to the power 5/4.

So here we can get.

N = 135 * Root of 10000 Divided by 25 to the power 5/4.

N = 241.495 rpm => ANSWER.

Sougata ghosh said:
8 years ago

I don't know, please help me.

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