Mechanical Engineering - Heat Transfer, Refrigeration and Air Conditioning - Discussion

Discussion Forum : Heat Transfer, Refrigeration and Air Conditioning - Section 6 (Q.No. 33)
33.
When α is absorptivity, ρ is reflectivity and τ is transmittivity, then for a diathermanous body,
α = 1, ρ = 0 and τ = 0
α = 0, ρ = 1 and τ = 0
α = 0, ρ = 0 and τ = 1
α + ρ = 1 and τ = 0
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
15 comments Page 1 of 2.

Jayesh said:   3 years ago
I think C is the correct answer.

Vikram said:   4 years ago
The Right answer is C.

Vinay said:   5 years ago
The Right answer is C.

Abhishek verma said:   5 years ago
The Right answr is C.

Uttada sai kumar said:   5 years ago
When α is absorptivity, ρ is reflectivity and τ is transmissivity, then for a diathermanous body,

For a transparent body α=0, ρ=0, τ=1, and Є < Transparent body is also called a Diathermanous body.

So, I think the given answer is wrong.

Rajat said:   6 years ago
C is the correct option.

Shaikh salman said:   6 years ago
Diathermanous body is a body which transmits all the incident radiation without absorbing or reflecting. (A body with transmitivity 1, reflectivity 0 and absorptivity 0) Air, up to certain extent can be considered as the diathermanous body because, it transmits all the radiation without hearing itself.

RoCky. said:   6 years ago
No, it is wrong.

Because of T=0 for Opaque body.

The diathermanous body is a transparent body : T=1.

Arun said:   6 years ago
C is the correct answer T=1 (transmittivity is 1 for diathermanous).

Tin said:   6 years ago
How C is correct?


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