Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 40)
40.
Mass moment of inertia of a uni form thin rod of mass M and length (l) about its mid-point and perpendicular to its length is
Discussion:
23 comments Page 3 of 3.
Debattam Dey said:
4 years ago
This answer is absolutely correct.
Where, an axis passing through its C.G mid point and perpendicular to its length for that, Ig= 1/12 ml^2.
And, an axis passing through C.G at the end point to the parallel axis on its length for that expression, Ig= 1/3 ml^2.
So, the answer is correct. I hope it will be helpful to us.
Where, an axis passing through its C.G mid point and perpendicular to its length for that, Ig= 1/12 ml^2.
And, an axis passing through C.G at the end point to the parallel axis on its length for that expression, Ig= 1/3 ml^2.
So, the answer is correct. I hope it will be helpful to us.
(1)
Debisa Adugna said:
4 years ago
B is correct.
According to parallel axis theorem;
= 1/12ml2 + 1/3(l/2)2,
= 1/12ml2 + 1/4ml2,
4ml2/12ml2,
= 1/3ml2.
According to parallel axis theorem;
= 1/12ml2 + 1/3(l/2)2,
= 1/12ml2 + 1/4ml2,
4ml2/12ml2,
= 1/3ml2.
Ashok said:
3 years ago
I think the correct answer is 1/3ml^2.
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