Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 40)
40.
Mass moment of inertia of a uni form thin rod of mass M and length (l) about its mid-point and perpendicular to its length is
Discussion:
23 comments Page 1 of 3.
Siva reddi said:
6 years ago
The moment of inertia of thin rod of mass M and length L about an axis passing through its centre of gravity and perpendicular to its length is Ig=ml^2/12.
And the moment of inertia about a parallel axis through one end of the rod is Ip=ml^2/3. Here the question mentioned midpoint so the midpoint is nothing but A centre of gravity so the answer is option D.
And the moment of inertia about a parallel axis through one end of the rod is Ip=ml^2/3. Here the question mentioned midpoint so the midpoint is nothing but A centre of gravity so the answer is option D.
Debattam Dey said:
4 years ago
This answer is absolutely correct.
Where, an axis passing through its C.G mid point and perpendicular to its length for that, Ig= 1/12 ml^2.
And, an axis passing through C.G at the end point to the parallel axis on its length for that expression, Ig= 1/3 ml^2.
So, the answer is correct. I hope it will be helpful to us.
Where, an axis passing through its C.G mid point and perpendicular to its length for that, Ig= 1/12 ml^2.
And, an axis passing through C.G at the end point to the parallel axis on its length for that expression, Ig= 1/3 ml^2.
So, the answer is correct. I hope it will be helpful to us.
(1)
Saikumar said:
1 decade ago
For a uniform rod with negligible thickness, the moment of inertia about its center of mass is 1/12 ml^2.
The moment of inertia about the end of the rod can be calculated directly or obtained from the center of mass expression by use of the Parallel axis theorem. 1/3 ml^2.
The moment of inertia about the end of the rod can be calculated directly or obtained from the center of mass expression by use of the Parallel axis theorem. 1/3 ml^2.
AJP said:
7 years ago
Here Q is mi at mid perpendicular to the length.
Mi at mid parallel to axis equal 1/12 ml^2.
Mi at mid perpendicular to axis equal 1/3 ml^2.
So the answer should be B.
Mi at mid parallel to axis equal 1/12 ml^2.
Mi at mid perpendicular to axis equal 1/3 ml^2.
So the answer should be B.
Kp baloda said:
8 years ago
Mass moment of inertia generally used when there is motion and area moi is used in structure design. Both are moment of inertia.
Debisa Adugna said:
4 years ago
B is correct.
According to parallel axis theorem;
= 1/12ml2 + 1/3(l/2)2,
= 1/12ml2 + 1/4ml2,
4ml2/12ml2,
= 1/3ml2.
According to parallel axis theorem;
= 1/12ml2 + 1/3(l/2)2,
= 1/12ml2 + 1/4ml2,
4ml2/12ml2,
= 1/3ml2.
Varun said:
9 years ago
What is the difference between the moment of inertia & mass moment of inertia?
Uttudon said:
7 years ago
The given answer [D] is correct.
Option [B] is for MOI about rod end.
Option [B] is for MOI about rod end.
(1)
Boss said:
8 years ago
The given answer [D] is correct.
Option [B] is for MOI about rod end.
Option [B] is for MOI about rod end.
Selva said:
8 years ago
Which answer is correct? Please tell me with the explanation.
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