Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 40)
40.
Mass moment of inertia of a uni form thin rod of mass M and length (l) about its mid-point and perpendicular to its length is
Discussion:
23 comments Page 1 of 3.
Ashok said:
3 years ago
I think the correct answer is 1/3ml^2.
Debisa Adugna said:
4 years ago
B is correct.
According to parallel axis theorem;
= 1/12ml2 + 1/3(l/2)2,
= 1/12ml2 + 1/4ml2,
4ml2/12ml2,
= 1/3ml2.
According to parallel axis theorem;
= 1/12ml2 + 1/3(l/2)2,
= 1/12ml2 + 1/4ml2,
4ml2/12ml2,
= 1/3ml2.
Debattam Dey said:
4 years ago
This answer is absolutely correct.
Where, an axis passing through its C.G mid point and perpendicular to its length for that, Ig= 1/12 ml^2.
And, an axis passing through C.G at the end point to the parallel axis on its length for that expression, Ig= 1/3 ml^2.
So, the answer is correct. I hope it will be helpful to us.
Where, an axis passing through its C.G mid point and perpendicular to its length for that, Ig= 1/12 ml^2.
And, an axis passing through C.G at the end point to the parallel axis on its length for that expression, Ig= 1/3 ml^2.
So, the answer is correct. I hope it will be helpful to us.
(1)
Siva reddi said:
6 years ago
The moment of inertia of thin rod of mass M and length L about an axis passing through its centre of gravity and perpendicular to its length is Ig=ml^2/12.
And the moment of inertia about a parallel axis through one end of the rod is Ip=ml^2/3. Here the question mentioned midpoint so the midpoint is nothing but A centre of gravity so the answer is option D.
And the moment of inertia about a parallel axis through one end of the rod is Ip=ml^2/3. Here the question mentioned midpoint so the midpoint is nothing but A centre of gravity so the answer is option D.
Kishan Gohil said:
6 years ago
Given answer is correct, ml2/3 is end of the rod.
Vicky bala said:
7 years ago
Option B is the correct Answer.
AJP said:
7 years ago
Here Q is mi at mid perpendicular to the length.
Mi at mid parallel to axis equal 1/12 ml^2.
Mi at mid perpendicular to axis equal 1/3 ml^2.
So the answer should be B.
Mi at mid parallel to axis equal 1/12 ml^2.
Mi at mid perpendicular to axis equal 1/3 ml^2.
So the answer should be B.
Prasad said:
7 years ago
According to me, it is 1/3MI^2.
Uttudon said:
7 years ago
The given answer [D] is correct.
Option [B] is for MOI about rod end.
Option [B] is for MOI about rod end.
(1)
SIDDAPPA said:
7 years ago
Which is the correct answer? Please describe it clearly.
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