Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 32)
32.
The centre of gravity of an equilateral triangle with each side a, is __________ from any of the three sides.
Discussion:
11 comments Page 1 of 2.
Rahul G said:
5 years ago
Then bisect anyone angle as well as the side of the triangle which bisects the angle and draws perpendicular on the side through bisected point.
We get right angle triangle which has a 30-degree angle and base side a/2.
Using this data we can apply trigonometry tan (θ) = h/(a/2)
Since θ=30.
h is an answer which is = a/2(√)3.
We get right angle triangle which has a 30-degree angle and base side a/2.
Using this data we can apply trigonometry tan (θ) = h/(a/2)
Since θ=30.
h is an answer which is = a/2(√)3.
Hriday said:
7 years ago
Draw a triangle take its height h & side a.
Then apply Pythagoras theorem for the half of the equilateral triangle.
Wll get a*2=h*2 +(a/2) *2.
Find the value of h.
Put in cg formula = h/3.
Then apply Pythagoras theorem for the half of the equilateral triangle.
Wll get a*2=h*2 +(a/2) *2.
Find the value of h.
Put in cg formula = h/3.
MD SALAHUDDIN said:
7 years ago
h2 = a2-(a/2)2,
h=root3*a/2,
cg=h/3, =a/2√3.
h=root3*a/2,
cg=h/3, =a/2√3.
Raju said:
8 years ago
(a*root3)/6 = (a*root3)/2*3=(a*root3)/2*root3*root3 = a/2*root3.
Clement said:
9 years ago
They just converted the same answer.
(root(3) * a/6)= a/(2 * root3).
(root(3) * a/6)= a/(2 * root3).
J.Jayakumar said:
10 years ago
How is it come?
Felix said:
10 years ago
If you rationalize [a/2*root (3)], it will give [a*root (3)/6].
Check it out.
Check it out.
Ram Kadam said:
10 years ago
Answer is ( root(3)*a)/6).
Mounika said:
1 decade ago
How would we be known to take Pythagoras theorem?
Jay said:
1 decade ago
Isn't the answer h = root(3)*a/6?
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