Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 32)
32.
The centre of gravity of an equilateral triangle with each side a, is __________ from any of the three sides.
Discussion:
11 comments Page 2 of 2.
Junaid Shaikh said:
1 decade ago
According to Pythagoras theorem:
a^2 = h^2+(a^2/4).
Therefore, h = (roor3/2)*a.
And we know that,
C.G of triangle from its base is h/3.
Hence h = a/(2*root3).
a^2 = h^2+(a^2/4).
Therefore, h = (roor3/2)*a.
And we know that,
C.G of triangle from its base is h/3.
Hence h = a/(2*root3).
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