Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 49)
49.
two like parallel forces are acting at a distance of 24 mm apart and their resultant is 20 N. It the line of action of the resultant is 6 mm from any given force, the two forces are
Discussion:
24 comments Page 3 of 3.
Sujit said:
5 years ago
Let they are P &Q apart 24 mm & Assume Resultant acts at 6mm from left force means 18mm from right side (18+6=24mm).
Now we get moment about Resultant i.e. 6mm from left &18mm from right we get eq.
6P-18Q=0-> eq.1; i.e(submation of moment=0).
P+ Q = 20-> eq.2; i.e ( Resultant is 20).
After solving the above eq. We get value 15&5N.
Now we get moment about Resultant i.e. 6mm from left &18mm from right we get eq.
6P-18Q=0-> eq.1; i.e(submation of moment=0).
P+ Q = 20-> eq.2; i.e ( Resultant is 20).
After solving the above eq. We get value 15&5N.
(2)
Arpan Acharya said:
5 years ago
Thank you all for explaining.
Rajesh Kadam said:
5 years ago
F1 + F2 = 20
F1*24 = R * 18
SOLVING Eq we get;
F1 = 15.
F2 = 5.
F1*24 = R * 18
SOLVING Eq we get;
F1 = 15.
F2 = 5.
(5)
Suman said:
4 years ago
Here, the Resultant is 20N, So a summation of F1 & F2 will be also 20N.
Hence, Only option (a) is suitable as its sum of two numbers (15+5) is equal to 20N.
Hence, Only option (a) is suitable as its sum of two numbers (15+5) is equal to 20N.
(2)
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