Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 49)
49.
two like parallel forces are acting at a distance of 24 mm apart and their resultant is 20 N. It the line of action of the resultant is 6 mm from any given force, the two forces are
Discussion:
24 comments Page 2 of 3.
POPPY said:
9 years ago
Resultant R = F1 + F2 = 20N (i) F1----6mm-----R------18mm------------F2 equating clockwise moment to anticlockwise moment then, 18F2 = 6F1 THEN, F1 = 3F2, From equating in (i) we get F1=15 &F2 = 5.
Lova said:
9 years ago
Thank you very much friends.
Rahul s said:
8 years ago
Thank you very much @Pandees Waran.
KRISH REDDY said:
8 years ago
Simple method friends.
All forces equal to the resultant is 20.
So see the option s where the 2 forces are 20 so that will be the answer. 5+15=20.
All forces equal to the resultant is 20.
So see the option s where the 2 forces are 20 so that will be the answer. 5+15=20.
Prashant Ranjan said:
8 years ago
F1 !---6mm--*-----18mm--------! F2.
Anti-clockwise moment = Clockwise moment
F1*6 = F2*18
F1 = 3F2--------------(1)
F1+F2 = 20 ( given)
F1 = 20-F2------------(2)
From (1) and (2), we get
3F2 = 20-F2.
F2 = 5 kn.
F1 = 3F2 =3*5=15kn.
Anti-clockwise moment = Clockwise moment
F1*6 = F2*18
F1 = 3F2--------------(1)
F1+F2 = 20 ( given)
F1 = 20-F2------------(2)
From (1) and (2), we get
3F2 = 20-F2.
F2 = 5 kn.
F1 = 3F2 =3*5=15kn.
(2)
Nikss said:
8 years ago
@ALL.
Two forces acting parallel in the same direction. So the resultant will be a single force in the same direction. So from where this clockwise and anticlockwise concept came?
All forces will be in same direction.
Two forces acting parallel in the same direction. So the resultant will be a single force in the same direction. So from where this clockwise and anticlockwise concept came?
All forces will be in same direction.
Faisal said:
8 years ago
Thanks @Roj.
(1)
Kaku said:
7 years ago
F1 + F2 = 20N.
Taking moment about B.
R*0= -f1(6)+ f2(24-6),
0 = -(20-f2)(6) + 18f2,
F2 =5.
After putting we will get the answer.
Taking moment about B.
R*0= -f1(6)+ f2(24-6),
0 = -(20-f2)(6) + 18f2,
F2 =5.
After putting we will get the answer.
(3)
Sanjeev said:
7 years ago
Thanks @Roj.
Praveen said:
6 years ago
This is to be solved by Varignon's Theorem.
Consider a point A.
Moment of F1 about A + Moment of F2 about A = Moment of R about A.
Consider a point A.
Moment of F1 about A + Moment of F2 about A = Moment of R about A.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers