Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 49)
49.
two like parallel forces are acting at a distance of 24 mm apart and their resultant is 20 N. It the line of action of the resultant is 6 mm from any given force, the two forces are
Discussion:
24 comments Page 1 of 3.
Suman said:
4 years ago
Here, the Resultant is 20N, So a summation of F1 & F2 will be also 20N.
Hence, Only option (a) is suitable as its sum of two numbers (15+5) is equal to 20N.
Hence, Only option (a) is suitable as its sum of two numbers (15+5) is equal to 20N.
(2)
Rajesh Kadam said:
5 years ago
F1 + F2 = 20
F1*24 = R * 18
SOLVING Eq we get;
F1 = 15.
F2 = 5.
F1*24 = R * 18
SOLVING Eq we get;
F1 = 15.
F2 = 5.
(5)
Arpan Acharya said:
5 years ago
Thank you all for explaining.
Sujit said:
5 years ago
Let they are P &Q apart 24 mm & Assume Resultant acts at 6mm from left force means 18mm from right side (18+6=24mm).
Now we get moment about Resultant i.e. 6mm from left &18mm from right we get eq.
6P-18Q=0-> eq.1; i.e(submation of moment=0).
P+ Q = 20-> eq.2; i.e ( Resultant is 20).
After solving the above eq. We get value 15&5N.
Now we get moment about Resultant i.e. 6mm from left &18mm from right we get eq.
6P-18Q=0-> eq.1; i.e(submation of moment=0).
P+ Q = 20-> eq.2; i.e ( Resultant is 20).
After solving the above eq. We get value 15&5N.
(2)
Praveen said:
6 years ago
This is to be solved by Varignon's Theorem.
Consider a point A.
Moment of F1 about A + Moment of F2 about A = Moment of R about A.
Consider a point A.
Moment of F1 about A + Moment of F2 about A = Moment of R about A.
Sanjeev said:
7 years ago
Thanks @Roj.
Kaku said:
7 years ago
F1 + F2 = 20N.
Taking moment about B.
R*0= -f1(6)+ f2(24-6),
0 = -(20-f2)(6) + 18f2,
F2 =5.
After putting we will get the answer.
Taking moment about B.
R*0= -f1(6)+ f2(24-6),
0 = -(20-f2)(6) + 18f2,
F2 =5.
After putting we will get the answer.
(3)
Faisal said:
8 years ago
Thanks @Roj.
(1)
Nikss said:
8 years ago
@ALL.
Two forces acting parallel in the same direction. So the resultant will be a single force in the same direction. So from where this clockwise and anticlockwise concept came?
All forces will be in same direction.
Two forces acting parallel in the same direction. So the resultant will be a single force in the same direction. So from where this clockwise and anticlockwise concept came?
All forces will be in same direction.
Prashant Ranjan said:
8 years ago
F1 !---6mm--*-----18mm--------! F2.
Anti-clockwise moment = Clockwise moment
F1*6 = F2*18
F1 = 3F2--------------(1)
F1+F2 = 20 ( given)
F1 = 20-F2------------(2)
From (1) and (2), we get
3F2 = 20-F2.
F2 = 5 kn.
F1 = 3F2 =3*5=15kn.
Anti-clockwise moment = Clockwise moment
F1*6 = F2*18
F1 = 3F2--------------(1)
F1+F2 = 20 ( given)
F1 = 20-F2------------(2)
From (1) and (2), we get
3F2 = 20-F2.
F2 = 5 kn.
F1 = 3F2 =3*5=15kn.
(2)
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