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Mechanical Engineering - Engineering Mechanics - Discussion

Discussion Forum : Engineering Mechanics - Section 2 (Q.No. 31)
Engineering Mechanics
31.
Which of the following statement is correct?
The kinetic energy of a body during impact remains constant.
The kinetic energy of a body before impact is equal to the kinetic energy of a body after impact.
The kinetic energy of a body before impact is less than the kinetic energy of a body after impact.
The kinetic energy of a body before impact is more than the kinetic energy of a body after impact.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
13 comments Page 1 of 2.
Ramji verma said:   6 years ago
When condition is not given then we assume that condition is ideal.
Vasantharaj M J said:   6 years ago
Is it for elastic, inelastic, plastic or real case? Please tell me.
Scientist sakthivel said:   8 years ago
For perfect elastic body, loss of K.E iske1=ke2
And perfectly plastic impact K.E=(ke1-ke2)
Energy can't be negative.
So K.E1 is greater than KE2.
(1)
Balu said:   8 years ago
Given answer is correct if the collision is inelastic.
Montu said:   8 years ago
I think after impact the stress induced in the body was more so it will directly affect the energy consumption rate and also change in moment of area.
Ranjan said:   8 years ago
Yes, you are right @Paresh.
Raushan kumar said:   8 years ago
It is not cleared that what types of collision occur. Hence answer should be a, b & d depending on types of collision.
Vaishali said:   8 years ago
Here, it is not said the body is elastic hence answer is d.
Amit said:   9 years ago
According to me, The correct answer will be B or D.
Akash said:   9 years ago
I think C is the correct answer.
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