Mechanical Engineering - Engineering Mechanics - Discussion

How it is possible?

How can we classify upward projectile and downward projectile?

In inclined projectile

R=(u^2)/g(1(+/-)sin deta ) for up +, down -.

So,
For 45 deg ,1/(1+sin45) is 1.4.
And same, 1/(1-sin45) is 3.3.
Therefore
Down > up.

Range of projectile in a downward inclined is given by
R= (2u^2sin(a+b)cosa)/gcos^2b
Range of projectile in an upward inclined is given by
R= (2u^2sin(a-b)cosa)/gcos^2b
Where 'a' is alpha, angle made by projection with horizontal and 'b' is beta, angle made by range with horizontal.
Since the value of sin* increase from 0° to 90° and (a+b) is greater than (a-b)
The range of projectile in a downward inclined is greater than Range of the projectile in an upward inclined.

How come a range of projectile on the downward inclined plane will be more? Should it be less na?

Because speed will be more, as gravity is acting, so that distance will be covered in less time. Please, someone, clarify.

What is projectile?

Projectile is object which is projected either upward or downward.

A projectile is an object upon which the only force acting is gravity.

Range of a projectile is the maximum distance travelled by it during time of flight.

Range of projectile is the distance between point at which the projectile is projected and reaching the ground.