Mechanical Engineering - Engineering Mechanics - Discussion

When projectile moves upward its velocity reduce because negative gravitational acceleration there for time increase to reach same height but time taken to reach the ground less due to ground. And distance (range) = v/t.

As t increases d reduce &t reduce d increase. There for distance (range) inversely proportional to time.

I think they will be of the same values even if the plane that is being his is inclined up or down. They will his only a particular point with respect to horizontal distance (i.e. Range).

But the height of impact will change depending on the inclination. Agree. ?

How to work projectile?

Range of projectile in a downward inclined is given by
R= (2u^2sin(a+b)cosa)/gcos^2b
Range of projectile in an upward inclined is given by
R= (2u^2sin(a-b)cosa)/gcos^2b
Where 'a' is alpha, angle made by projection with horizontal and 'b' is beta, angle made by range with horizontal.
Since the value of sin* increase from 0° to 90° and (a+b) is greater than (a-b)
The range of projectile in a downward inclined is greater than Range of the projectile in an upward inclined.

Rang or projectile always depends on projection angle.

The max range got in 45°.

During upword prjectile accleration due to gravity act negetively and during its act (+). So valocity during downward direction is more.

I think it's equal because of 'same velocity'.

Range means the horizontal distance covered by projectile.

How it is possible?

How can we classify upward projectile and downward projectile?