Mechanical Engineering - Engineering Mechanics - Discussion

Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 7)
7.
The range of projectile on a downward inclined plane is __________ the range on upward inclined plane for the same velocity of projection and angle of projection.
less than
more than
equal to
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
46 comments Page 1 of 5.

Nagaraju said:   2 months ago
Upward force only one cosθ.
Downward forces are gravitational and sinθ.

Ola said:   3 years ago
As the projectile travels through the air, the horizontal component of velocity remains constant, but the vertical component of velocity changes due to the effect of gravity, which pulls the projectile downward.

This results in the projectile travelling a greater horizontal distance before it hits the ground.
(7)

Neelam said:   5 years ago
Yes, the main reason is the gravitational force of the earth.
(3)

Cephas said:   6 years ago
Because when it is down to top it experienced gravity thereby decreasing the velocity or the it speed.
(1)

Sandeep sanker said:   6 years ago
r=2usin^2(theta)/g. Here denominator is g so the range is inversely proportional to g. On uphill g has more influence on projectile than downhill so its range decreases.
(1)

Rahul Pal said:   7 years ago
@All.

Let me explain. Imagine you are standing on an upward inclined plane. Now when you make a projectile, you will have to overcome the peak and thus it reduces your range.

But when you are standing on a downward inclined plane, then you will be able to throw at any projectile and thus you will get a larger range.

(Imagine yourself firing an artillery gun from a mountain).
(4)

Prerana said:   7 years ago
How come a range of projectile on the downward inclined plane will be more? Should it be less na?

Because speed will be more, as gravity is acting, so that distance will be covered in less time. Please, someone, clarify.

Santosh Gandhari said:   8 years ago
Range of projectile in a downward inclined is given by
R= (2u^2sin(a+b)cosa)/gcos^2b
Range of projectile in an upward inclined is given by
R= (2u^2sin(a-b)cosa)/gcos^2b
Where 'a' is alpha, angle made by projection with horizontal and 'b' is beta, angle made by range with horizontal.
Since the value of sin* increase from 0° to 90° and (a+b) is greater than (a-b)
The range of projectile in a downward inclined is greater than Range of the projectile in an upward inclined.

Scientist sakthivel said:   8 years ago
In inclined projectile

R=(u^2)/g(1(+/-)sin deta ) for up +, down -.

So,
For 45 deg ,1/(1+sin45) is 1.4.
And same, 1/(1-sin45) is 3.3.
Therefore
Down > up.

Mr jalendar said:   8 years ago
I think answer is option B because of for example a stone you through in upward direction while coming return it will be more speed as you all know this simple technique thank you all.
(1)


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