Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 17)
17.
If the masses of both the bodies, as shown in the below figure, are reduced to 50 percent, then tension in the string will be
Discussion:
16 comments Page 1 of 2.
Nivesh said:
1 decade ago
Since T= (m1*m2/m1+m2) g.
So, tension will be halved (T/2) when both m1 & m2 are halved.
So, tension will be halved (T/2) when both m1 & m2 are halved.
Anil kumar Dhaked said:
1 decade ago
T = (m1*m2/m1+m2).g
So,Tension force will be 50 percent of T(T*50/100)when both m1 or m2 are 50% that means halves.
So,Tension force will be 50 percent of T(T*50/100)when both m1 or m2 are 50% that means halves.
Kaushik Das said:
1 decade ago
m1a-T = T-m2a.
Therefore T = (m1+m2)a/2 = X(say).
Now if masses are halved, then tension = X/2 = T/2.
Therefore T = (m1+m2)a/2 = X(say).
Now if masses are halved, then tension = X/2 = T/2.
PRIYA said:
1 decade ago
We know that,
F=ma.
Therefore T=ma.
T is directly proportional to m.
Thus m is reduced to half hence T is also reduced to half.
F=ma.
Therefore T=ma.
T is directly proportional to m.
Thus m is reduced to half hence T is also reduced to half.
Dileepkumar said:
1 decade ago
Tension is nothing but with small difference is equal to the force which is equal to the product of mass and acceleration. The tension is directly proportional to the mass.
Arogya said:
1 decade ago
T = (m1*m2)/(m1+m2).
When m value is reduced to half.
New tension may be assumed as T1.
Now T1 = ((m1/2)*(m2/2))/((m1/2)+(m2/2)).
T1 = (2/4)(m1*m2)/(m1+m2) = (1/2)(m1*m2)/(m1+m2) = T/2.
Therefore new tension also reduced to half.
When m value is reduced to half.
New tension may be assumed as T1.
Now T1 = ((m1/2)*(m2/2))/((m1/2)+(m2/2)).
T1 = (2/4)(m1*m2)/(m1+m2) = (1/2)(m1*m2)/(m1+m2) = T/2.
Therefore new tension also reduced to half.
(3)
Malik said:
1 decade ago
If body is in equilibrium than it means weight = tension; as weight reduces to 50% of original. So it is obvious that tension becomes half.
Meriolen said:
1 decade ago
Looking at the figure if mass is reduced equally on both sides irrespective of percentage, the tension reduces by the same amount. Simple logic.
Sharda said:
1 decade ago
From the formula.
T=Mg.
We know simply tension (T) is directly proportional to the mass of body (M). And hence 50 percent reduction in the mass reduces the same amount of tension in the string. Hence tension will be half.
T=Mg.
We know simply tension (T) is directly proportional to the mass of body (M). And hence 50 percent reduction in the mass reduces the same amount of tension in the string. Hence tension will be half.
Abhijit Sasmal said:
9 years ago
Tension in both side of the string will be equal because tension is directly proportional to the body mass. If reduce 50% in mass then tension will be half and equal to both side.
(1)
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