Mechanical Engineering - Engineering Mechanics - Discussion

Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 17)
17.
If the masses of both the bodies, as shown in the below figure, are reduced to 50 percent, then tension in the string will be
same
half
double
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
16 comments Page 1 of 2.

Vinay BEL said:   5 years ago
Since T= 2(m1*m2/m1+m2) g.
If we put the value of mass half.
So, the answer is [A].
(1)

Salim Ansari said:   5 years ago
T = mg + ma.
(1)

Paul said:   7 years ago
2T= (m'g+m"g).

Now 50% reduced from both:
2T* = .5(m'g+m"g) = .5X2T.
T* = .5T.
(2)

Vip said:   7 years ago
Here, F or T is directly proportional to mass M, when M is reduced 50 % then Force tension is also reduced 50 % means half.
(4)

GOURAV said:   8 years ago
Well explained @Arogya.
(1)

Imran Faizi said:   9 years ago
Tension is directly proportional to the mass of the body. If there is a certain amount of reduction in mass of the bodies then Tension (T) will also be reduced by the same amount. So it will be half.
(1)

Abhijit Sasmal said:   9 years ago
Tension in both side of the string will be equal because tension is directly proportional to the body mass. If reduce 50% in mass then tension will be half and equal to both side.
(1)

Sharda said:   1 decade ago
From the formula.

T=Mg.

We know simply tension (T) is directly proportional to the mass of body (M). And hence 50 percent reduction in the mass reduces the same amount of tension in the string. Hence tension will be half.

Meriolen said:   1 decade ago
Looking at the figure if mass is reduced equally on both sides irrespective of percentage, the tension reduces by the same amount. Simple logic.

Malik said:   1 decade ago
If body is in equilibrium than it means weight = tension; as weight reduces to 50% of original. So it is obvious that tension becomes half.


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