Mechanical Engineering - Engineering Mechanics - Discussion

Discussion Forum : Engineering Mechanics - Section 5 (Q.No. 9)
9.
In a single threaded worm and worm wheel, the number of teeth on the worm is 50. The diameter of the effort wheel is 100 mm and that of load drum is 50 mm. The velocity ratio is
50
100
150
200
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
11 comments Page 1 of 2.

Piyush savaliya said:   1 decade ago
Vr = RT/nr.
= 100*50/50.
= 100.

Patel Hitesh said:   1 decade ago
V.R = nD/D-d
= 50*100/100-50.
= 100.
(1)

Sanjay patel said:   9 years ago
As per system of pulley,

VR = Distance moved by effort/Distance moved by the load.

= PI * D * T/pi * d * t.
= 100 * 50/50.1.
= 100.

Suranjan said:   8 years ago
V.R = teeth on worm gear/no. Of thread.
T of worm/ T of worm gear = D of worm/D of worm gear.
50/T.w.g= 50/100,
T.w.g = 100,
V.R = 100/1= 100.

RAGHAVENDRA REDDY said:   8 years ago
V.R=distance moved by P(effort)/distance moved by W(load).

V.R=2*L/2*r/T=LT/r=50*50/25=100.

Uttu don said:   7 years ago
D/d.
100/50 = 2,
2*50 = 100.

Rishabh said:   6 years ago
LT/r, where L= radius of the wheel,
T = no.of teeth in worm wheel,
r = radius of load drum.
50*50/25.
2500/25.
= 100.
(2)

Vinay BEL said:   5 years ago
V.R = nD/D-d.
= 50*100/100-50.
= 100.
(2)

Praba said:   4 years ago
Here Vr = DT/2r.

Shiba Prasad Sahoo said:   3 years ago
Vr is 100.


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