Mechanical Engineering - Engineering Mechanics - Discussion

Discussion Forum : Engineering Mechanics - Section 2 (Q.No. 10)
10.
The maximum efficiency of a lifting machine is
1/m
V.R./m
m/V.R.
1/(m x V.R.)
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
16 comments Page 2 of 2.

Harsh said:   9 years ago
What is m here?

YOGENDRA SINGH said:   1 decade ago
MA = W/P,

From law of machine.

P = mW+C.

MA = 1/(m+C/W).

So in limiting case when W tends to infinity, then C/W = 0 and max mechanical advantage equals to 1/m.

So efficiency = MA/VR.

Max efficiency = 1/m*VR.

Krishna said:   1 decade ago
Efficieny = MA/VR.

If MA is Max then Eff is Max.

MA is Max when MA = 1/m we get MA = 1/m from law of machine P = mW+c.

Since MA = W/p and substituting P from law of machine we get MA max = 1/m.

So Eff = 1/m*VR.

Sanjay said:   1 decade ago
M means Mechanical advance and VR means Velocity Ratio.

Naveen K said:   1 decade ago
Please mention what these M, V, R indicates?

Robo said:   1 decade ago
If someone knows the explanation for this question please explain here.


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