Mechanical Engineering - Engineering Mechanics - Discussion

Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 36)
36.
The angle between two forces when the resultant is maximum and minimum respectively are
0° and 180°
180° and 0°
90° and 180°
90° and 0°
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
12 comments Page 1 of 2.

Adebc said:   1 decade ago
Resultant of 2 forces will be minimum at 180 degree since the move in opposite direction e.g 4-1=3 but maximum at 0 degree. the same direction
e.g 4+1=5.

Anil kumar dhaked said:   1 decade ago
From R^2 = P^2+Q^2+2*P*Q*Cos(Theta).

If value of theta = 0° then cos(theta) = 1.

Then R^2 = P^2+Q^2(Maximum).
And
Value of theta =180°Cos(Theta) = -1(negative).

Then R^2 = P^2-Q^2(Minimum).

Patrick said:   9 years ago
I disagree. Applying cosine rule R^2 = P^2 + Q^2 - 2PQcos (theta).

Cos0 = 1 (which maintains a negative sign hence obtain a minimum value).

Cos180 = - 1 (which converts the negative sign to positive hence obtains a maximum value).

Aravibd said:   9 years ago
If θ = 0.
R = (P + Q)^2.

If θ =180.
R= (P-Q)^2.

Substitute values for p and q. We will get the answer.

Ashish Mahajan said:   9 years ago
@Anil.

Your explanation is correct, only thing is that,
R = P - Q when theta is 180 degree.

Keyur Patel said:   8 years ago
There is simple logic when two forces in same direction (0 degree) resultant is max. But they are opposite each other (180 degree) resultant force is min.
(1)

Shubham tambekar said:   7 years ago
Thanks @Keyur.

Lakhan bhavnani said:   7 years ago
Thanks @Keyur.

Uah said:   7 years ago
Thanks @Keyur Patel.

Saraki Yaman Alhaji said:   7 years ago
It should be 180° and 0°.
(1)


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